PCl_5 ⇌ PCl_3+ Cl_2 K_c =1.844 3.0 moles of PCl_5 is introduced in a 1 L closed reaction vessel at 380 K. The number of moles of PCl_5 at equilibrium…

$$\mathrm{PCl}_5 \rightleftharpoons \mathrm{PCl}_3+\mathrm{Cl}_2 \quad \mathrm{~K}_{\mathrm{c}}=1.844 $$ $\displaystyle 3.0$ moles of $\displaystyle \mathrm{PCl}_5$ is introduced in a $\displaystyle 1$ L closed reaction vessel at $\displaystyle 380$ K . The number of moles of $\displaystyle \mathrm{PCl}_5$ at equilibrium is \_\_\_\_ $\displaystyle \times 10^{-3}$. (Round off to the Nearest Integer)