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Physics · 2024 · 3 marks
CBSE 2024 · Region 3 · Set 3 · Q23
An electron (charge - e, mass m ) is revolving around a nucleus, in a hydrogen atom, in a circle of radius r. Derive an expression, in vector form,…
An electron (charge - e, mass m ) is revolving around a nucleus, in a hydrogen atom, in a circle of radius $\displaystyle r$. Derive an expression, in vector form, for the magnetic dipole moment, $\displaystyle \vec{\mu}_{\mathrm{e}}$ in terms of its orbital angular momentum $\displaystyle \overrightarrow{\mathrm{L}}$. What is gyromagnetic ratio?
Marking-scheme solution
Electron revolve around the nucleus constitute a current
\[\begin{aligned}
& \mathrm{I}=\mathrm{e} / T \\
& T=\frac{2 \pi r}{v}
\end{aligned}
\]
\[\mathrm{I}=\frac{\mathrm{e} v}{2 \pi r}
\]
Magnetic moment, \(\displaystyle \mathrm{M}=\mathrm{I} . \mathrm{A}\)
\[\begin{aligned}
& \mu_{l}=\frac{\mathrm{e} v \cdot \pi r^{2}}{2 \pi r} \\
& \mu_{l}=\frac{\mathrm{e} v r}{2} \\
& (\mathrm{L}=m v r)
\end{aligned}
\]
Since electron has negative charge, \(\displaystyle \mu_{l}\) is opposite in direction of an electron of angular momentum L.
\[\overrightarrow{\mu_{l}}=-\frac{\mathrm{e}}{2 m} \vec{\mathrm{L}}
\]
Gyromagnetic ratio- The ratio of magnetic moment to angular momentum is called gyromagnetic ratio.
That is, \(\displaystyle \frac{\mu_{\mathrm{e}}}{\mathrm{L}}=\frac{\mathrm{e}}{2 m}\)
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