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CBSE 2026 · Region 1 · Set 1 · Q25 · 3 marks

Figure: CBSE Class 12 Physics 2026, Semiconductor Electronics: Materials, Devices and Simple Circuits
An ac voltage $\displaystyle \mathrm{V}_{\mathrm{i}}=12 \sin (100 \pi \mathrm{t}) \mathrm{V}$ is applied between points A and B in a network of two ideal diodes and three resistors as shown in figure. During the positive half-cycle of the input voltage $\displaystyle \mathrm{V}_{\mathrm{i}}$ supplied to the network.
(a)
Identify which of the two diodes will conduct and why ?
(b)
Redraw an equivalent circuit diagram to show the flow of current.
(c)
Calculate the output voltage drops $\displaystyle \mathrm{V}_{0}$ across the three resistors when the input voltage attains its peak value.

Semiconductor Electronics: Materials, Devices and Simple CircuitsApplication of Junction Diode as a RectifierApplyshort_answermedium

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CBSE Class 12 Physics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.