CBSE 2025 · Region 6 · Set 1 · Q29 · 4 marks
A capacitor is a system of two conductors separated by an insulator. In practice, the two conductors have charges Q and -Q with potential difference $\displaystyle \mathrm{V}=\mathrm{V}_{1}-\mathrm{V}_{2}$ between them. The ratio $\displaystyle \frac{\mathrm{Q}}{\mathrm{V}}$ is a constant, denoted by $\displaystyle \mathrm{C}$ and is called the capacitance of the capacitor. It is independent of Q or V. It depends only on the geometrical configuration (shape, size, separation) of the two conductors and the medium separating the conductors. When a parallel plate capacitor is charged, the electric field $\displaystyle \mathrm{E}_{0}$ is localised between the plates and is uniform throughout. When a slab of a dielectric is inserted between the charged plates (charge density $\displaystyle \sigma$ ) , the dielectric is polarised by the field. Consequently opposite charges appear on the faces of the slab, near the plates, with surface charge density of magnitude $\displaystyle \sigma_{\mathrm{p}}$. For a linear dielectric $\displaystyle \sigma_{\mathrm{p}}$ is proportional to $\displaystyle \mathrm{E}_{0}$. Introduction of a dielectric changes the electric field, and hence, the capacitance of a capacitor, and hence, the energy stored in the capacitor. Like resistors, capacitors can also be arranged in series or in parallel or in a combination of series and parallel.(i)Consider a capacitor of capacitance C, with plate area A and plate separation d, filled with air[Fig. (a) ]. The distance between the plates is increased to $\displaystyle 2$ d and one of the plates is shifted as shown in Fig. (b) . The capacitance of the new system now is:
(a)
(A)$\displaystyle \frac{\mathrm{C}}{4}$(B)$\displaystyle \frac{\mathrm{C}}{2}$(C)$\displaystyle 2$ C(D)$\displaystyle 4$ C(ii)A slab (area A and thickness $\displaystyle \mathrm{d}_{1}$ ) of a linear dielectric of dielectric constant K is inserted between charged plates (charge density $\displaystyle \sigma$ ) of a parallel plate capacitor [plate area A and plate separation $\displaystyle \left.\mathrm{d}\left(>\mathrm{d}_{1}\right)\right]$ and opposite charges with charge density of magnitude $\displaystyle \sigma_{\mathrm{p}}$ appear on the faces of the slab. The dielectric constant K is given by :(A)$\displaystyle \frac{\sigma+\sigma_{\mathrm{p}}}{\sigma}$(B)$\displaystyle \frac{\sigma}{\sigma-\sigma_{\mathrm{p}}}$(C)$\displaystyle \frac{\sigma+\sigma_{\mathrm{p}}}{\sigma_{\mathrm{p}}}$(D)$\displaystyle \frac{\sigma}{\sigma_{\mathrm{p}}}$(iii)An electric field E is established between the plates of an air filled parallel plate capacitor, with charges Q and $\displaystyle -\mathrm{Q} . \mathrm{V}$ is the volume of the space enclosed between the plates. The energy stored in the capacitor is :(A)$\displaystyle \frac{1}{2} \varepsilon_{0} \mathrm{E}^{2}$(B)$\displaystyle \varepsilon_{0} \mathrm{Q}^{2} \mathrm{E}$(C)$\displaystyle \frac{1}{2} \varepsilon_{0} \mathrm{E}^{2} \mathrm{~V}$(D)$\displaystyle \varepsilon_{0} \mathrm{EQV}$(a)Three capacitors A, B and M, each of capacitance C are connected to a capacitor N of capacitance $\displaystyle 2$ C and a battery as shown in the figure. If the charges on A and N are Q and $\displaystyle \mathrm{Q}^{\prime}$ respectively, then $\displaystyle \frac{\mathrm{Q}^{\prime}}{\mathrm{Q}}$ is :
(A)$\displaystyle \frac{1}{6}$(B)$\displaystyle \frac{1}{3}$(C)$\displaystyle 3$
(D) $\displaystyle 6$OR(b) A slab (area A and thickness $\displaystyle \frac{\mathrm{d}}{2}$ ) of dielectric constant K is inserted in a parallel plate capacitor of plate area A and plate separation d . If C and $\displaystyle \mathrm{C}_{0}$ are the capacitances of the capacitors with and without the dielectric, then $\displaystyle \frac{\mathrm{C}}{\mathrm{C}_{0}}$ is :(A)$\displaystyle \frac{\mathrm{K}+1}{2 \mathrm{~K}}$(B)$\displaystyle \frac{2 \mathrm{~K}}{\mathrm{~K}+1}$(C)$\displaystyle \frac{\mathrm{K}}{\mathrm{K}-1}$(D)$\displaystyle \frac{\mathrm{K}-1}{\mathrm{~K}}$
A capacitor is a system of two conductors separated by an insulator. In practice, the two conductors have charges Q and -Q with potential difference $\displaystyle \mathrm{V}=\mathrm{V}_{1}-\mathrm{V}_{2}$ between them. The ratio $\displaystyle \frac{\mathrm{Q}}{\mathrm{V}}$ is a constant, denoted by $\displaystyle \mathrm{C}$ and is called the capacitance of the capacitor. It is independent of Q or V. It depends only on the geometrical configuration (shape, size, separation) of the two conductors and the medium separating the conductors. When a parallel plate capacitor is charged, the electric field $\displaystyle \mathrm{E}_{0}$ is localised between the plates and is uniform throughout. When a slab of a dielectric is inserted between the charged plates (charge density $\displaystyle \sigma$ ) , the dielectric is polarised by the field. Consequently opposite charges appear on the faces of the slab, near the plates, with surface charge density of magnitude $\displaystyle \sigma_{\mathrm{p}}$. For a linear dielectric $\displaystyle \sigma_{\mathrm{p}}$ is proportional to $\displaystyle \mathrm{E}_{0}$. Introduction of a dielectric changes the electric field, and hence, the capacitance of a capacitor, and hence, the energy stored in the capacitor. Like resistors, capacitors can also be arranged in series or in parallel or in a combination of series and parallel.
(i)
Consider a capacitor of capacitance C, with plate area A and plate separation d, filled with air[Fig. (a) ]. The distance between the plates is increased to $\displaystyle 2$ d and one of the plates is shifted as shown in Fig. (b) . The capacitance of the new system now is:
(a)
(A)
$\displaystyle \frac{\mathrm{C}}{4}$
(B)
$\displaystyle \frac{\mathrm{C}}{2}$
(C)
$\displaystyle 2$ C
(D)
$\displaystyle 4$ C
(ii)
A slab (area A and thickness $\displaystyle \mathrm{d}_{1}$ ) of a linear dielectric of dielectric constant K is inserted between charged plates (charge density $\displaystyle \sigma$ ) of a parallel plate capacitor [plate area A and plate separation $\displaystyle \left.\mathrm{d}\left(>\mathrm{d}_{1}\right)\right]$ and opposite charges with charge density of magnitude $\displaystyle \sigma_{\mathrm{p}}$ appear on the faces of the slab. The dielectric constant K is given by :
(A)
$\displaystyle \frac{\sigma+\sigma_{\mathrm{p}}}{\sigma}$
(B)
$\displaystyle \frac{\sigma}{\sigma-\sigma_{\mathrm{p}}}$
(C)
$\displaystyle \frac{\sigma+\sigma_{\mathrm{p}}}{\sigma_{\mathrm{p}}}$
(D)
$\displaystyle \frac{\sigma}{\sigma_{\mathrm{p}}}$
(iii)
An electric field E is established between the plates of an air filled parallel plate capacitor, with charges Q and $\displaystyle -\mathrm{Q} . \mathrm{V}$ is the volume of the space enclosed between the plates. The energy stored in the capacitor is :
(A)
$\displaystyle \frac{1}{2} \varepsilon_{0} \mathrm{E}^{2}$
(B)
$\displaystyle \varepsilon_{0} \mathrm{Q}^{2} \mathrm{E}$
(C)
$\displaystyle \frac{1}{2} \varepsilon_{0} \mathrm{E}^{2} \mathrm{~V}$
(D)
$\displaystyle \varepsilon_{0} \mathrm{EQV}$
(a)
Three capacitors A, B and M, each of capacitance C are connected to a capacitor N of capacitance $\displaystyle 2$ C and a battery as shown in the figure. If the charges on A and N are Q and $\displaystyle \mathrm{Q}^{\prime}$ respectively, then $\displaystyle \frac{\mathrm{Q}^{\prime}}{\mathrm{Q}}$ is :
(A)
$\displaystyle \frac{1}{6}$
(B)
$\displaystyle \frac{1}{3}$
(C)
$\displaystyle 3$
(D) $\displaystyle 6$
OR
(b) A slab (area A and thickness $\displaystyle \frac{\mathrm{d}}{2}$ ) of dielectric constant K is inserted in a parallel plate capacitor of plate area A and plate separation d . If C and $\displaystyle \mathrm{C}_{0}$ are the capacitances of the capacitors with and without the dielectric, then $\displaystyle \frac{\mathrm{C}}{\mathrm{C}_{0}}$ is :(A)
$\displaystyle \frac{\mathrm{K}+1}{2 \mathrm{~K}}$
(B)
$\displaystyle \frac{2 \mathrm{~K}}{\mathrm{~K}+1}$
(C)
$\displaystyle \frac{\mathrm{K}}{\mathrm{K}-1}$
(D)
$\displaystyle \frac{\mathrm{K}-1}{\mathrm{~K}}$
Marking-scheme solution
(i) (A) \(\displaystyle \left(\frac{\mathrm{C}}{4}\right)\)
(ii) (B) \(\displaystyle \frac{\sigma}{\sigma-\sigma_{\mathrm{p}}}\)
(iii) (C) \(\displaystyle \frac{1}{2} \varepsilon_{0} \mathrm{E}^{2} \mathrm{V}\)
(iv) (a) (D) $\displaystyle 6$ OR
(b) (B) \(\displaystyle \frac{2 \mathrm{K}}{\mathrm{K}+1}\)
Electrostatic Potential and CapacitanceCapacitors and CapacitanceApplycase_studymedium
Practice Electrostatic Potential and Capacitance →All Electrostatic Potential and Capacitance questions
More from Electrostatic Potential and Capacitance
- (i) A parallel plate capacitor with plate area A and plate separation d has a capacitance C 0. A slab of…2025 · asked 3×
- (i) In the figure, OA and OB show the variation of electric potential V at a point due to two point charges Q…2026 · asked 3×
- Two metal spheres of radii r 1 and r 2( r 1) having charges q 1 and q 2 respectively kept in air, are brought…2026 · asked 3×
- (i) Explain the following statements giving reason: (I) An equipotential surface through a point is normal to…2026 · asked 3×
- A parallel plate capacitor has two parallel plates which are separated by an insulating medium like air,…2025 · asked 3×
- (i) Derive an expression for potential energy of an electric dipole p in an external uniform electric field…2024 · asked 3×
- Dielectrics play an important role in design of capacitors. The molecules of a dielectric may be polar or…2024 · asked 3×
- The figure shows four pairs of parallel identical conducting plates, separated by the same distance 2.0 cm…2024 · asked 3×
CBSE Class 12 Physics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.