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Mathematics · 2025 · 1 mark
CBSE 2025 · Region 6 · Set 1 · Q10
Let f^′( x )=3( x^2+2 x )-4/(x^3)+5, f(1)=0. Then, f( x ) is:
Let $\displaystyle f^{\prime}(\mathrm{x})=3\left(\mathrm{x}^{2}+2 \mathrm{x}\right)-\frac{4}{\mathrm{x}^{3}}+5, f(1)=0$. Then, $\displaystyle f(\mathrm{x})$ is :
Official answer
(B)
$\displaystyle \mathrm{x}^{3}+3 \mathrm{x}^{2}+\frac{2}{\mathrm{x}^{2}}+5 \mathrm{x}-11$
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CBSE Class 12 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.