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Mathematics · 2026 · 1 mark
CBSE 2026 · Region 5 · Set 1 · Q6
If f( x )= {(x^2-4 x -5)/(x +1), x ≠-1; k, x =-1} is continuous at x =-1, then the value of k is:
If $\displaystyle f(\mathrm{x})=\left\{\begin{array}{cc}\frac{\mathrm{x}^{2}-4 \mathrm{x}-5}{\mathrm{x}+1}, & \mathrm{x} \neq-1 \\ k, & \mathrm{x}=-1\end{array}\right.$ is continuous at $\displaystyle \mathrm{x}=-1$, then the value of k is :
Official answer
(D)
$\displaystyle -6$
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