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Mathematics · 2025 · 1 mark
CBSE 2025 · Region 6 · Set 1 · Q6
If f( x )= {(log (1+ a x )+ log (1- b x ))/x, for x ≠ 0; k, for x =0} is continuous at x =0, then the value of k is:
If $\displaystyle f(\mathrm{x})=\left\{\begin{array}{cc}\frac{\log (1+\mathrm{a} \mathrm{x})+\log (1-\mathrm{b} \mathrm{x})}{\mathrm{x}}, & \text { for } \mathrm{x} \neq 0 \\ k, & \text { for } \mathrm{x}=0\end{array}\right.$ is continuous at $\displaystyle \mathrm{x}=0$, then the value of k is :
Official answer
(C)
$\displaystyle \mathrm{a}-\mathrm{b}$
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