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Mathematics · 2025 · 1 mark
CBSE 2025 · Region 6 · Set 1 · Q7
If tan^-1( x^2- y^2)= a, where ' a ' is a constant, then (d y)/(d x) is:
If $\displaystyle \tan ^{-1}\left(\mathrm{x}^{2}-\mathrm{y}^{2}\right)=\mathrm{a}$, where ' $\displaystyle \mathrm{a}$ ' is a constant, then $\displaystyle \frac{d \mathrm{y}}{d \mathrm{x}}$ is :
Official answer
(A)
$\displaystyle \frac{\mathrm{x}}{\mathrm{y}}$
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CBSE Class 12 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.