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CBSE 2025 · Region 6 · Set 1 · Q7 · 1 mark

If $\displaystyle \tan ^{-1}\left(\mathrm{x}^{2}-\mathrm{y}^{2}\right)=\mathrm{a}$, where ' $\displaystyle \mathrm{a}$ ' is a constant, then $\displaystyle \frac{d \mathrm{y}}{d \mathrm{x}}$ is :

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