CBSE 2025 · Region 4 · Set 1 · Q12 · 1 mark
The function f defined by \[f(\mathrm{x})= \begin{cases}\mathrm{x}, & \text { if } \mathrm{x} \leq 1 \\ 5, & \text { if } \mathrm{x}>1\end{cases} \] is not continuous at :
Official answer
From CBSE’s own marking scheme for this paper.
(B)
$\displaystyle \mathrm{x}=1$
Continuity and DifferentiabilityContinuityUnderstandmcqeasy
More from Continuity and Differentiability
- If f(x)=. is continuous at x=0, then the value of a is:2025 · asked 4×
- The value of k for which function f(x)=. is differentiable at x=0 is:2023 · asked 3×
- If y=( cos x- sin x)/( cos x+ sin x), then (d y)/(d x) is:2023 · asked 3×
- If f(x)=. is continuous at x=0, then the value of k is:2025 · asked 3×
- Differentiate sec^-1( 1√1-x^2) w.r.t. sin^-1(2 x √1-x^2). OR If y= tan x+ sec x, then prove that (d^2 y)/(d…2023 · asked 3×
- If f(x)=. is continuous at x=-1, then the value of k is:2026 · asked 3×
- The value of k for which the function f(x)= casesx^2 sin 1/x, & x ≠ 0 k(x+1), & x=0 cases is a continuous…2026 · asked 3×
- If tan ((x+y)/(x-y))=k, then (dy)/(dx) is equal to2023 · asked 3×
CBSE Class 12 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.