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Mathematics · 2025 · 1 mark
CBSE 2025 · Region 7 · Set 3 · Q8
If f(x)= {3 a x-b, x>1; 11, x=1; -5 a x-2 b, x<1} is continuous at x=1, then the values of a and b are:
If $\displaystyle f(x)=\left\{\begin{array}{cc}3 \mathrm{a} x-b & , x>1 \\ 11 & , x=1 \\ -5 \mathrm{a} x-2 b & , x<1\end{array}\right.$ is continuous at $\displaystyle x=1$, then the values of $\displaystyle \mathrm{a}$ and $\displaystyle b$ are :
Official answer
(C)
$\displaystyle \mathrm{a}=1, \mathrm{~b}=-8$
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CBSE Class 12 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.