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Mathematics · 2025 · 1 mark
CBSE 2025 · Region 7 · Set 1 · Q12
∫ (e^9 log x - e^8 log x)/(e^6 log x - e^5 log x) dx is equal to:
$\displaystyle \int \frac{\mathrm{e}^{9 \log \mathrm{x}}-\mathrm{e}^{8 \log \mathrm{x}}}{\mathrm{e}^{6 \log \mathrm{x}}-\mathrm{e}^{5 \log \mathrm{x}}} \mathrm{dx}$ is equal to :
Official answer
(C)
$\displaystyle \frac{\mathrm{x}^{4}}{4}+\mathrm{C}$
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CBSE Class 12 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.