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Mathematics · 2025 · 1 mark
CBSE 2025 · Region 5 · Set 2 · Q12
If ∫_0^a 1/(1+4 x^2) dx =(π)/8, then the value of 'a' is:
If $\displaystyle \int_{0}^{\mathrm{a}} \frac{1}{1+4 \mathrm{x}^{2}} \mathrm{dx}=\frac{\pi}{8}$, then the value of 'a' is :
Official answer
(B)
$\displaystyle \frac{1}{2}$
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CBSE Class 12 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.