CBSE 2023 · Region 3 · Set 1 · Q28 · 3 marks
Evaluate : \[\int_{1}^{\mathrm{e}} \frac{1}{\sqrt{4 \mathrm{x}^{2}-(\mathrm{x} \log \mathrm{x})^{2}}} d \mathrm{x} \]
Marking-scheme solution
$$\begin{aligned}
& \text { Let } \mathrm{I}=\int_{1}^{\mathrm{e}} \frac{1}{\sqrt{4 \mathrm{x}^{2}-(\mathrm{x} \log \mathrm{x})^{2}}} \mathrm{dx} \\
& =\int_{1}^{\mathrm{e}} \frac{1}{\mathrm{x} \sqrt{4-(\log \mathrm{x})^{2}}} \mathrm{dx} \quad\left[\text { Let } \log \mathrm{x}=\mathrm{t} \Rightarrow \frac{1}{\mathrm{x}} \mathrm{dx}=\mathrm{dt}\right] \\
& =\int_{0}^{1} \frac{d \mathrm{t}}{\sqrt{4-\mathrm{t}^{2}}} \\
& =\left.\sin ^{-1} \frac{\mathrm{t}}{2}\right|_{0} ^{1}=\frac{\pi}{6}
\end{aligned}
$$
IntegralsEvaluation of Definite Integrals by SubstitutionApplyshort_answerhard
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CBSE Class 12 Mathematics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.