A convex mirror used for rear view on an automobile has a focal length of 1.5 m. If a 3 m high bus is located at 6.0 m from the mirror, use mirror…

Here \(\displaystyle f=+1.5 \mathrm{~m} ; \mathrm{u}=-6.0 \mathrm{~m} ; \mathrm{h}=3 \mathrm{~m}\) \[\frac{1}{v}+\frac{1}{u}=\frac{1}{f} \] \(\displaystyle \frac{1}{v}+\frac{1}{-6}=\frac{1}{1.5} \frac{1}{\mathrm{v}}=\frac{1}{6}+\frac{1}{1.5} \mathrm{v}=\frac{6}{5}=1.2 \mathrm{~m} \frac{\mathrm{h}^{\prime}}{\mathrm{h}}=\frac{-\mathrm{v}}{\mathrm{u}} \frac{\mathrm{h}^{\prime}}{3}=\frac{1.2}{6} \mathrm{h}^{\prime}=0.6 \mathrm{~m}\)