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Science · 2024 · 3 marks
CBSE 2024 · Region 2 · Set 2 · Q31
(a)An object is placed in front of a concave mirror of focal length $\displaystyle 12$ cm. If distance of the object from the pole of the mirror is $\displaystyle 8$ cm, then use mirror formula to determine the position of the image formed. Draw a labelled ray diagram to justify your answer in this case.OR 31. (b) (i) The image of an object formed by a mirror is real, inverted and is of magnification-1. If the image is at a distance of $\displaystyle 30$ cm from the mirror, where is the object placed ? Give reason to justify your answer.(ii)Where would the image be if the object is moved $\displaystyle 15$ cm towards the mirror ? Draw ray diagram for the new position of the object to justify your answer.
(a)
An object is placed in front of a concave mirror of focal length $\displaystyle 12$ cm. If distance of the object from the pole of the mirror is $\displaystyle 8$ cm, then use mirror formula to determine the position of the image formed. Draw a labelled ray diagram to justify your answer in this case.
OR 31. (b) (i) The image of an object formed by a mirror is real, inverted and is of magnification-1. If the image is at a distance of $\displaystyle 30$ cm from the mirror, where is the object placed ? Give reason to justify your answer.
(ii)
Where would the image be if the object is moved $\displaystyle 15$ cm towards the mirror ? Draw ray diagram for the new position of the object to justify your answer.
Marking-scheme solution
(a)
Here \(\displaystyle f=-12 \mathrm{~cm}, u=-8 \mathrm{~cm}, v=\) ?
Mirror formula \(\displaystyle \frac{1}{v}+\frac{1}{u}=\frac{1}{f}\)
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CBSE Class 10 Science past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.