With the help of above given ray diagram, calculate the angle of refraction. Given that the refractive index of Medium $\displaystyle 2$ with respect to Medium $\displaystyle 1$ is $\displaystyle \sqrt{3}$.

\[\frac{\operatorname{Sin} \mathrm{i}}{\operatorname{Sin} \mathrm{r}}=\mathrm{n} \] \(\displaystyle \angle \mathrm{i}=90^{\circ}-30^{\circ}=60^{\circ}\) \(\displaystyle \operatorname{Sin} \mathrm{r}=\frac{\operatorname{Sin} \mathrm{i}}{\mathrm{n}}\) \(\displaystyle \operatorname{Sin} \mathrm{r}=\frac{\operatorname{Sin} 60}{\sqrt{3}}\) \(\displaystyle \operatorname{Sin} \mathrm{r}=\frac{\sqrt{3}}{2 \sqrt{3}}\) \(\displaystyle \operatorname{Sin} \mathrm{r}=\frac{1}{2} \Rightarrow \operatorname{Sin} \mathrm{r}=\operatorname{Sin} 30\) \[r=30^{\circ} \]