Exercise 4.6
Begin plotting points on the graph paper to represent each set of time and position values from Table 4.3. (i) Table shows that at time s, the position is also m. The point corresponding to this set of values on the graph will therefore be the origin itself. (ii) At s, the position of vehicle is at m. To mark these values, look for the point that represents s on the X-axis. Draw a line parallel to the Y-axis at
Not cross-checked
NCERT prints no numerical answer for this exercise, so this working has not been cross-checked against the book.
The seven points to be plotted from Table $\displaystyle 4.3$ are ($\displaystyle 0$ s, $\displaystyle 0$ m), ($\displaystyle 1$ s, $\displaystyle 20$ m), ($\displaystyle 2$ s, $\displaystyle 40$ m), ($\displaystyle 3$ s, $\displaystyle 60$ m), ($\displaystyle 4$ s, $\displaystyle 80$ m), ($\displaystyle 5$ s, $\displaystyle 100$ m) and ($\displaystyle 6$ s, $\displaystyle 120$ m).
Axes and scale: time along the X-axis with $\displaystyle 5$ divisions \(\displaystyle = 1\ \text{s} \), position along the Y-axis with $\displaystyle 5$ divisions \(\displaystyle = 20\ \text{m} \).
The point ($\displaystyle 0$ s, $\displaystyle 0$ m) needs no construction — it is the origin O itself.
For ($\displaystyle 1$ s, $\displaystyle 20$ m): draw a line parallel to the Y-axis through the $\displaystyle 1$ s mark on the X-axis, and a line parallel to the X-axis through the $\displaystyle 20$ m mark on the Y-axis; the point where the two lines intersect is the required point.
Repeat this construction for the remaining pairs. The seven points come out equally spaced and all lie along one straight line.