Physics · 2021
JEE Main · 16 March 2021, Shift 2 · Q12
The half-life of Au^198 is 2.7 days. The activity of 1.50 mg of Au^198 if its atomic weight is 198 g mol^-1 is, ( N_A =6 × 10^23 / mol ).
The half-life of $\displaystyle \mathrm{Au}^{198}$ is $\displaystyle 2.7$ days. The activity of $\displaystyle 1.50$ mg of $\displaystyle \mathrm{Au}^{198}$ if its atomic weight is $\displaystyle 198 \mathrm{~g} \mathrm{~mol}^{-1}$ is, $\displaystyle \left(\mathrm{N}_{\mathrm{A}}=6 \times 10^{23} / \mathrm{mol}\right)$.
Official answer
(2)
$\displaystyle 357$ Ci
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.