Physics · 2023
JEE Main · 6 April 2023, Shift 2 · Q56
Experimentally it is found that 12.8 eV energy is required to separate a hydrogen atom into a proton and an electron. So the orbital radius of the…
Experimentally it is found that $\displaystyle 12.8$ eV energy is required to separate a hydrogen atom into a proton and an electron. So the orbital radius of the electron in a hydrogen atom is $\displaystyle \frac{9}{x} \times 10^{-10} \mathrm{~m}$. The value of the $\displaystyle x$ is: $\displaystyle \_\_\_\_$.
$\displaystyle \left(1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}, \frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{Nm}^2 / \mathrm{C}^2\right.$ and electronic charge $\displaystyle \left.=1.6 \times 10^{-19} \mathrm{C}\right)$
Official answer
From NTA’s final answer key for this paper.
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.