Physics · 2026
JEE Main · 5 April 2026, Shift 1 · Q36
In the hydrogen atom, the electron makes a transition from the higher orbit (i) to a lower orbit (f). The ratio of the radius of the orbits in given…
In the hydrogen atom, the electron makes a transition from the higher orbit (i) to a lower orbit $\displaystyle (f)$. The ratio of the radius of the orbits in given by $\displaystyle r_i: r_f=16: 4$. The wavelength of photon emitted due to this transition is $\displaystyle \_\_\_\_$ nm.
(Given Rydberg constant $\displaystyle =1.0973 \times 10^7 / \mathrm{m}$ )
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 486$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.