Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a nucleus of mass number 10. If the binding energy per nucleon for…

Two nuclei of mass number $\displaystyle 3$ combine with another nucleus of mass number $\displaystyle 4$ to yield a nucleus of mass number 10. If the binding energy per nucleon for the mass numbers $\displaystyle 3$, $\displaystyle 4$ and $\displaystyle 10$ are $\displaystyle 5.6$ MeV, $\displaystyle 7.4$ MeV and $\displaystyle 6.1$ MeV, respectively, then in the process, $\displaystyle \Delta \mathrm{Mc}^2=$ $\displaystyle \_\_\_\_$ MeV.