Physics · 2025
JEE Main · 2 April 2025, Shift 2 · Q38
Energy released when two deuterons (_1 H^2) fuse to form a helium nucleus (_2 He^4) is: (Given: Binding energy per nucleon of _1 H^2=1.1 MeV and…
Energy released when two deuterons $\displaystyle \left({ }_1 \mathrm{H}^2\right)$ fuse to form a helium nucleus $\displaystyle \left({ }_2 \mathrm{He}^4\right)$ is : (Given : Binding energy per nucleon of $\displaystyle { }_1 \mathrm{H}^2=1.1 \mathrm{MeV}$ and binding energy per nucleon of $\displaystyle { }_2 \mathrm{He}^4=7.0 \mathrm{MeV}$ )
Official answer
From NTA’s final answer key for this paper.
(3)
23.$\displaystyle 6$ MeV
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.