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Physics · 2026

JEE Main · 21 January 2026, Shift 2 · Q44

The energy of an electron in an orbit of the Bohr's atom is -0.04 E_0 eV where E_0 is the ground state energy. If L is the angular momentum of the…

The energy of an electron in an orbit of the Bohr's atom is $\displaystyle -0.04 E_0 \mathrm{eV}$ where $\displaystyle E_0$ is the ground state energy. If $\displaystyle L$ is the angular momentum of the electron in this orbit and $\displaystyle h$ is the Planck's constant, then $\displaystyle \frac{2 \pi L}{h}$ is $\displaystyle \_\_\_\_$:
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.