Physics · 2020
JEE Main · 8 January 2020, Shift 2 · Q25
The first member of the Balmer series of hydrogen atom has a wavelength of 6561. The wavelength of the second member of the Balmer series (in nm) is…
The first member of the Balmer series of hydrogen atom has a wavelength of $\displaystyle 6561 \AA$. The wavelength of the second member of the Balmer series (in nm) is
\_\_\_\_.
Official answer
486
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.