Physics · 2019
JEE Main · 12 April 2019, Shift 2 · Q25
The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The…
The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths, $\displaystyle \lambda_1 / \lambda_2$, of the photons emitted in this process is :
Official answer
(4)
$\displaystyle 20$/$\displaystyle 7$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.