Physics · 2021
JEE Main · 17 March 2021, Shift 2 · Q27
The disc of mass M with uniform surface mass density σ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the…
The disc of mass $\displaystyle M$ with uniform surface mass density $\displaystyle \sigma$ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position $\displaystyle \frac{x}{3} \frac{\mathrm{a}}{\pi}, \frac{x}{3} \frac{\mathrm{a}}{\pi}$ where $\displaystyle x$ is \_\_\_\_. (Round off to the Nearest Integer)
[a is an area as shown in the figure]

Official answer
4
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.