Physics · 2020
JEE Main · 6 September 2020, Shift 2 · Q4
Particle A of mass m_1 moving with velocity (√ 3 i + j ) ms^-1 collides with another particle B of mass m_2 which is at rest initially. Let V_1 and…
Particle A of mass $\displaystyle \mathrm{m}_1$ moving with velocity $\displaystyle (\sqrt{3} \hat{i}+\hat{j}) \mathrm{ms}^{-1}$ collides with another particle B of mass $\displaystyle m_2$ which is at rest initially. Let $\displaystyle \overrightarrow{\mathrm{V}}_1$ and $\displaystyle \overrightarrow{\mathrm{V}}_2$ be the velocities of particles A and B after collision respectively. If $\displaystyle \mathrm{m}_1=2 \mathrm{~m}_2$ and after collision $\displaystyle \overrightarrow{\mathrm{V}}_1=(\hat{i}+\sqrt{3} \hat{j}) \mathrm{ms}^{-1}$, the angle between $\displaystyle \vec{V}_1$ and $\displaystyle \vec{V}_2$ is :
Official answer
(3)
$\displaystyle 105$°
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.