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Physics · 2024

JEE Main · 1 February 2024, Shift 1 · Q52

The identical spheres each of mass 2 M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 4 m each.…

The identical spheres each of mass $\displaystyle 2$ M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to $\displaystyle 4$ m each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is $\displaystyle \frac{4 \sqrt{2}}{x}$, where the value of $\displaystyle x$ is $\displaystyle \_\_\_\_$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.