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Physics · 2022

JEE Main · 28 July 2022, Shift 2 · Q22

The distance of centre of mass from end A of a one dimensional rod ( A B ) having mass density ρ=ρ_0(1-x^2/L^2) kg / m and length L (in meter) is (3…

The distance of centre of mass from end $\displaystyle A$ of a one dimensional rod ( $\displaystyle A B$ ) having mass density $\displaystyle \rho=\rho_0\left(1-\frac{x^2}{L^2}\right) \mathrm{kg} / \mathrm{m}$ and length L (in meter) is $\displaystyle \frac{3 L}{\alpha} \mathrm{~m}$. The value of $\displaystyle \alpha$ is \_\_\_\_. (where $\displaystyle x$ is the distance from end A )
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.