SolveIt is under development
SolveItJEE Main
Physics · 2023

JEE Main · 10 April 2023, Shift 1 · Q56

The decay constant for a radioactive nuclide is 1.5 × 10^-5 s^-1. Atomic weight of the substance is 60 g mole ^-1,(N_A=6 × 10^23). The activity of…

The decay constant for a radioactive nuclide is $\displaystyle 1.5 \times 10^{-5} \mathrm{~s}^{-1}$. Atomic weight of the substance is $\displaystyle 60$ g mole $\displaystyle { }^{-1},\left(N_A=6 \times 10^{23}\right)$. The activity of $\displaystyle 1.0 \mu \mathrm{~g}$ of the substance is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{10} \mathrm{~Bq}$.
ShareWhatsAppTelegram

More from Atoms and Nuclei

JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.