Physics · 2020
JEE Main · 2 September 2020, Shift 1 · Q18
In a reactor, 2 kg of _92 U^235 fuel is fully used up in 30 days. The energy released per fission is 200 MeV. Given that the Avogadro number, N…
In a reactor, $\displaystyle 2$ kg of $\displaystyle { }_{92} \mathrm{U}^{235}$ fuel is fully used up in $\displaystyle 30$ days. The energy released per fission is $\displaystyle 200$ MeV . Given that the Avogadro number, $\displaystyle \mathrm{N}=6.023 \times 10^{26}$ per kilo mole and $\displaystyle 1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}$. The power output of the reactor is close to :
Official answer
(1)
$\displaystyle 60$ MW
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.