Physics · 2022
JEE Main · 27 June 2022, Shift 2 · Q48
Given below are two statements: Statement I: In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit (…
Given below are two statements:
Statement I: In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit $\displaystyle \left(\mathrm{E}_1\right)$ to higher energy orbit $\displaystyle \left(\mathrm{E}_2\right)$, is given as $\displaystyle h f=\mathrm{E}_1-\mathrm{E}_2$
Statement II: The jumping of electron from higher energy orbit $\displaystyle \left(\mathrm{E}_2\right)$ to lower energy orbit $\displaystyle \left(\mathrm{E}_1\right)$ is associated with frequency of radiation given as
$$f=\left(\mathrm{E}_2-\mathrm{E}_1\right) / h
$$
This condition is Bohr's frequency condition.
In the light of the above statements, choose the correct answer from the options given below:
Official answer
(4)
Statement I is incorrect but statement II is true.
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.