Find the Binding energy per neucleon for _50^120 Sn. Mass of proton m_p =1.00783 U, mass of neutron m_n =1.00867 U and mass of tin nucleus m_Sn…

Find the Binding energy per neucleon for $\displaystyle { }_{50}^{120} \mathrm{Sn}$. Mass of proton $\displaystyle \mathrm{m}_{\mathrm{p}}=1.00783 \mathrm{U}$, mass of neutron $\displaystyle \mathrm{m}_{\mathrm{n}}=1.00867 \mathrm{U}$ and mass of tin nucleus $\displaystyle \mathrm{m}_{\mathrm{Sn}}=119.902199 \mathrm{U}$. (take $\displaystyle 1 \mathrm{U}=931 \mathrm{MeV}$ )