Physics · 2020
JEE Main · 8 January 2020, Shift 2 · Q4
As shown in fig. when a spherical cavity (centred at O ) of radius 1 is cut out of a uniform sphere of radius R (centred at C), the centre of mass of…
As shown in fig. when a spherical cavity (centred at O ) of radius $\displaystyle 1$ is cut out of a uniform sphere of radius R (centred at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e on the surface of the cavity. R can be determined by the equation :Official answer
(3)
$\displaystyle \left(R^2+R+1\right)(2-R)=1$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.