Physics · 2023
JEE Main · 1 February 2023, Shift 2 · Q18
An electron of a hydrogen like atom, having Z=4, jumps from 4^th energy state to 2^nd energy state. The energy released in this process, will be:…
An electron of a hydrogen like atom, having $\displaystyle Z=4$, jumps from $\displaystyle 4^{\text {th }}$ energy state to $\displaystyle 2^{\text {nd }}$ energy state.
The energy released in this process, will be :
(Given $\displaystyle \mathrm{Rch}=13.6 \mathrm{eV}$ )
Where R = Rydberg constant
c = Speed of light in vacuum
h = Planck's constant
Official answer
From NTA’s final answer key for this paper.
(1)
40.$\displaystyle 8$ eV
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.