Physics · 2019
JEE Main · 12 January 2019, Shift 1 · Q26
A particle of mass m moves in a circular orbit in a central potential field U ( r )=1/2 kr^2. If Bohr's quantization conditions are applied, radii of…
A particle of mass $\displaystyle m$ moves in a circular orbit in a central potential field $\displaystyle \mathrm{U}(\mathrm{r})=\frac{1}{2} \mathrm{kr}^2$. If Bohr's quantization conditions are applied, radii of possible orbitls and energy levels vary with quantum number n as :
Official answer
(4)
$\displaystyle \mathrm{r}_{\mathrm{n}} \propto \sqrt{\mathrm{n}}, \quad \mathrm{E}_{\mathrm{n}} \propto \mathrm{n}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.