Physics · 2023
JEE Main · 1 February 2023, Shift 1 · Q23
A light of energy 12.75 eV is incident on a hydrogen atom in its ground state. The atom absorbs the radiation and reaches to one of its excited…
A light of energy $\displaystyle 12.75$ eV is incident on a hydrogen atom in its ground state. The atom absorbs the radiation and reaches to one of its excited states. The angular momentum of the atom in the excited state is $\displaystyle \frac{x}{\pi} \times 10^{-17} \mathrm{eVs}$. The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$ (use $\displaystyle h=4.14 \times 10^{-15} \mathrm{eVs}, c=3 \times 10^8 \mathrm{~ms}^{-1}$ ).
Official answer
From NTA’s final answer key for this paper.
828
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.