Physics · 2016
JEE Main · 9 April 2016, Shift 1 · Q22
A hydrogen atom makes a transition from n=2 to n=1 and emits a photon. This photon strikes a doubly ionized lithium atom (z=3) in excited state and…
A hydrogen atom makes a transition from $\displaystyle n=2$ to $\displaystyle n=1$ and emits a photon. This photon strikes a doubly ionized lithium atom $\displaystyle (z=3)$ in excited state and completely removes the orbiting electron. The least quantum number for the excited state of the ion for the process is :
Official answer
(3)
$\displaystyle 4$
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JEE Main 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.