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Physics · 2023

JEE Main · 12 April 2023, Shift 1 · Q60

A common example of alpha decay is _92^238 U →_90^234 Th +_2 He^4+ Q Given: _92^238 U =238.05060 u, _90^234 Th =234.04360 u, _2^4 He =4.00260 u and 1…

A common example of alpha decay is $${ }_{92}^{238} \mathrm{U} \longrightarrow{ }_{90}^{234} \mathrm{Th}+{ }_2 \mathrm{He}^4+\mathrm{Q} $$ Given : $$\begin{aligned} & { }_{92}^{238} \mathrm{U}=238.05060 \mathrm{u}, \\ & { }_{90}^{234} \mathrm{Th}=234.04360 \mathrm{u}, \\ & { }_2^4 \mathrm{He}=4.00260 \mathrm{u} \text { and } \\ & 1 \mathrm{u}=931.5 \frac{\mathrm{MeV}}{c^2} \end{aligned} $$ The energy released (Q) during the alpha decay of $\displaystyle { }_{92}^{238} \mathrm{U}$ is $\displaystyle \_\_\_\_$ MeV
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.