Mathematics · 2021
JEE Main · 27 August 2021, Shift 2 · Q83
3 × 7^22+2 × 10^22-44 when divided by 18 leaves the remainder \ \ \ \.
$\displaystyle 3 \times 7^{22}+2 \times 10^{22}-44$ when divided by $\displaystyle 18$ leaves the remainder \_\_\_\_.
Official answer
15
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.