Mathematics · 2024
JEE Main · 31 January 2024, Shift 1 · Q24
In the expansion of (1+x)(1-x^2)(1+3/x+3/x^2+1/x^3)^5, x ≠ 0, the sum of the coefficients of x^3 and x^-13 is equal to ____
In the expansion of $\displaystyle (1+x)\left(1-x^2\right)\left(1+\frac{3}{x}+\frac{3}{x^2}+\frac{1}{x^3}\right)^5, x \neq 0$, the sum of the coefficients of $\displaystyle x^3$ and $\displaystyle x^{-13}$ is equal to $\displaystyle \_\_\_\_$
Official answer
From NTA’s final answer key for this paper.
118
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.