Mathematics · 2026
JEE Main · 21 January 2026, Shift 2 · Q21
If (1/(^15 C_0)+1/(^15 C_1))(1/(^15 C_1)+1/(^15 C_2)) ⋯(1/(^15 C_12)+1/(^15 C_13))=(α^13)/(^14 C_0^14 C_1 …^14 C_12), then 30 α is equal to ____.
If $\displaystyle \left(\frac{1}{{ }^{15} \mathrm{C}_0}+\frac{1}{{ }^{15} \mathrm{C}_1}\right)\left(\frac{1}{{ }^{15} \mathrm{C}_1}+\frac{1}{{ }^{15} \mathrm{C}_2}\right) \cdots\left(\frac{1}{{ }^{15} \mathrm{C}_{12}}+\frac{1}{{ }^{15} \mathrm{C}_{13}}\right)=\frac{\alpha^{13}}{{ }^{14} \mathrm{C}_0{ }^{14} \mathrm{C}_1 \ldots{ }^{14} \mathrm{C}_{12}}$, then $\displaystyle 30 \alpha$ is equal to
$\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
32
More from Binomial Theorem
- If the sum of the coefficients of x^7 and x^14 in the expansion of (1/x^3-x^4)^n, x ≠ 0, is zero, then the value of n is ____.2026
- The number of elements in the set S={(r, k): k ∈ Z. and.^36 C_r+1=(6(^35 C_r))/((k^2-3))}, is:2026
- If for 3 ≤ r ≤ 30,(^30 C_30-r)+3(^30 C_31-r)+3(^30 C_32-r)+(^30 C_33-r)=^m C_r, then m equals:2026
- If the coefficients of the middle terms in the binomial expansions of (1+α x)^26 and (1-α x)^28, α ≠ 0, are equal, then the value of α is:2026
- In the expansion of (9 x-1/(3 √x))^18, x>0, if the term independent of x is (221)k, then k is equal to:2026
- Let the smallest value of k ∈ N, for which the coefficient of x^3 in (1+x)^3+(1+x)^4+(1+x)^5+…+(1+x)^99+(1+k x)^100, x ≠ 0, is (43 n+101/4)(^100 C_3)…2026
- The coefficient of x^2 in the expansion of (2 x^2+1/x)^10, x ≠ 0, is:2026
- If 26(2^3/3(^12 C_2)+2^5/5(^12 C_4)+2^7/7(^12 C_6)+⋯+(2^13)/13(^12 C_12))=3^13-α, then α is equal to:2026
JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.