Mathematics · 2021
JEE Main · 27 August 2021, Shift 1 · Q80
Σ_k =0^20(^20 C_k )^2 is equal to:
$\displaystyle \sum_{\mathrm{k}=0}^{20}\left({ }^{20} \mathrm{C}_{\mathrm{k}}\right)^2$ is equal to :
Official answer
(3)
$\displaystyle { }^{40} \mathrm{C}_{20}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.