Mathematics · 2021
JEE Main · 31 August 2021, Shift 1 · Q81
If (3^6/4^4) k is the term, independent of x, in the binomial expansion of (x/4-12/x^2)^12, then k is equal to \ \ \ \.
If $\displaystyle \left(\frac{3^6}{4^4}\right) \mathrm{k}$ is the term, independent of $\displaystyle x$, in the binomial expansion of $\displaystyle \left(\frac{x}{4}-\frac{12}{x^2}\right)^{12}$, then k is equal to \_\_\_\_.
Official answer
55
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.