Mathematics · 2019
JEE Main · 9 April 2019, Shift 2 · Q84
The vertices B and C of a ABC lie on the line, (x+2)/3=(y-1)/0=z/4 such that BC =5 units. Then the area (in sq. units) of this triangle, given that…
The vertices B and C of a $\displaystyle \triangle \mathrm{ABC}$ lie on the line, $\displaystyle \frac{x+2}{3}=\frac{y-1}{0}=\frac{z}{4}$ such that $\displaystyle \mathrm{BC}=5$ units. Then the area (in sq. units) of this triangle, given that the point A($\displaystyle 1$, -$\displaystyle 1$, $\displaystyle 2$), is :
Official answer
(2)
$\displaystyle \sqrt{34}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.