Mathematics · 2019
JEE Main · 9 April 2019, Shift 2 · Q83
Let P be the plane, which contains the line of intersection of the planes, x+y+z-6=0 and 2 x+3 y+z+5=0 and it is perpendicular to the x y -plane.…
Let P be the plane, which contains the line of intersection of the planes, $\displaystyle x+y+z-6=0$ and $\displaystyle 2 x+3 y+z+5=0$ and it is perpendicular to the $\displaystyle x y$-plane. Then the distance of the point ($\displaystyle 0$, $\displaystyle 0$, $\displaystyle 256$) from P is equal to :
Official answer
(2)
$\displaystyle 11 / \sqrt{5}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.