Mathematics · 2022
JEE Main · 30 July 2022, Shift 2 · Q77
Let a x+b y+c z+3=0 be the plane which bisects the acute angle between the planes 2 x-y-2 z+3=0 and 3 x-2 y+6 z+8=0. Then a+b+c is equal to
Let $\displaystyle a x+b y+c z+3=0$ be the plane which bisects the acute angle between the planes $\displaystyle 2 x-y-2 z+3=0$ and $\displaystyle 3 x-2 y+6 z+8=0$. Then $\displaystyle a+b+c$ is equal to
Official answer
(2)
$\displaystyle 28$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.