Mathematics · 2026
JEE Main · 6 April 2026, Shift 2 · Q20
The value of the integral ∫_-1^1((x^3+|x|+1)/(x^2+2|x|+1)) d x is equal to:
The value of the integral $\displaystyle \int_{-1}^1\left(\frac{x^3+|x|+1}{x^2+2|x|+1}\right) \mathrm{d} x$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 2 \log _{\mathrm{e}} 2$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.