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Mathematics · 2026

JEE Main · 8 April 2026, Shift 2 · Q16

The value of the integral ∫_0^2 (√(x(x^2+x+1)))/((√(x+1))(√(x^4+x^2+1))) d x is equal to:

The value of the integral $\displaystyle \int_0^2 \frac{\sqrt{x\left(x^2+x+1\right)}}{(\sqrt{x+1})\left(\sqrt{x^4+x^2+1}\right)} \mathrm{d} x$ is equal to :
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.