Mathematics · 2026
JEE Main · 4 April 2026, Shift 1 · Q19
Let ∫_-2^2(| sin x|+[x sin x]) d x=2(3- cos 2)+β, where [·] is the greatest integer function. Then β sin ((β)/2) equals:
Let $\displaystyle \int_{-2}^2(|\sin x|+[x \sin x]) d x=2(3-\cos 2)+\beta$, where $\displaystyle [\cdot]$ is the greatest integer function. Then $\displaystyle \beta \sin \left(\frac{\beta}{2}\right)$ equals:
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 2$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.